18.1 Redox Reactions and Oxidation Numbers

Learning Objectives

By the end of this section, you will be able to:

  • Identify the oxidation number for each element in a redox reaction
  • Describe defining traits of redox chemistry
  • Identify the oxidant and reductant of a redox reaction

Oxidation-Reduction Reactions

Earth’s atmosphere contains about 20% molecular oxygen, O2, a chemically reactive gas that plays an essential role in the metabolism of aerobic organisms and in many environmental processes that shape the world. The term was originally used to describe chemical reactions involving O2, but its meaning has evolved to refer to a broad and important reaction class known as . A few examples of such reactions will be used to develop a clear picture of this classification.

Some redox reactions involve the transfer of electrons between reactant species to yield ionic products, such as the reaction between sodium and chlorine to yield sodium chloride:


2Na(s) + Cl2(g) → 2NaCl(s)

It is helpful to view the process with regard to each individual reactant, that is, to represent the fate of each reactant in the form of an equation called a :


2Na(s) → 2Na+(s) + 2e
Cl2(g) + 2e− → 2Cl(s)

These equations show that Na atoms lose electrons while Cl atoms (in the Cl2 molecule) gain electrons, the “s” subscripts for the resulting ions signifying they are present in the form of a solid ionic compound. For redox reactions of this sort, the loss and gain of electrons define the complementary processes that occur:


oxidation = loss of electrons
reduction = gain of electrons

In this reaction, then, sodium is and chlorine undergoes . Viewed from a more active perspective, sodium functions as a , since it provides electrons to (or reduces) chlorine. Likewise, chlorine functions as an , as it effectively removes electrons from (oxidizes) sodium.


reducing agent = species that is oxidized
oxidizing agent = species that is reduced

Some redox processes, however, do not involve the transfer of electrons. Consider, for example, a reaction similar to the one yielding NaCl: 


H2(g) + Cl2(g) → 2HCl(g)

The product of this reaction is a covalent compound, so transfer of electrons in the explicit sense is not involved. To clarify the similarity of this reaction to the previous one and permit an unambiguous definition of redox reactions, a property called has been defined. The oxidation number (or oxidation state) of an element in a compound is the charge its atoms would possess if the compound were ionic. The following guidelines are used to assign oxidation numbers to each element in a molecule or ion.

Assigning Oxidation Numbers

  1. The oxidation number of an atom in an elemental substance is zero.
  2. The oxidation number of a monatomic ion is equal to the ion’s charge.
  3. Oxidation numbers for common nonmetals are usually assigned as follows:
    • Hydrogen: +1 when combined with nonmetals, −1 when combined with metals
    • Oxygen: −2 in most compounds, sometimes −1 (so-called peroxides, O22−), very rarely −1/2 (so-called superoxides, O2), positive values when combined with F (values vary)
    • Halogens: −1 for F always, −1 for other halogens except when combined with oxygen or other halogens (positive oxidation numbers in these cases, varying values)
  4. The sum of oxidation numbers for all atoms in a molecule or polyatomic ion equals the charge on the molecule or ion.

Note: The proper convention for reporting charge is to write the number first, followed by the sign (e.g., 2+), while oxidation number is written with the reversed sequence, sign followed by number (e.g., +2). This convention aims to emphasize the distinction between these two related properties.

Example 18.1a

Assigning Oxidation Numbers

Follow the guidelines in this section of the text to assign oxidation numbers to all the elements in the following species:

  1. H2S
  2. SO32−
  3. Na2SO4


  1. According to guideline 3, the oxidation number for H is +1.
    Using this oxidation number and the compound’s formula, guideline 4 may then be used to calculate the oxidation number for sulfur:
    charge on H2S=0=(2 × +1) + (1 × x)

    x = 0−(2 × +1) = −2
  2. Guideline 3 suggests the oxidation number for oxygen is −2.
    Using this oxidation number and the ion’s formula, guideline 4 may then be used to calculate the oxidation number for sulfur:
    charge on SO32− = −2 =(3 × −2) + (1 × x)
    x = −2 − (3 × −2) = +4
  3. For ionic compounds, it’s convenient to assign oxidation numbers for the cation and anion separately.
    According to guideline 2, the oxidation number for sodium is +1.
    Assuming the usual oxidation number for oxygen (−2 per guideline 3), the oxidation number for sulfur is calculated as directed by guideline 4:
    charge on SO42− = −2 = (4 × −2) + (1 × x)
    x = −2 − (4 × −2)= +6

Exercise 18.1a

Assign oxidation states to the elements whose atoms are underlined (the underlined elements are a. N, b. A, c. N, d. P) in each of the following compounds or ions:

  1. KNO3
  2. AlH3
  3. NH4+
  4. H2PO4

Check Your Answers[1]

Using the oxidation number concept, an all-inclusive definition of redox reaction has been established. Oxidation-reduction (redox) reactions are those in which one or more elements involved undergo a change in oxidation number. (While the vast majority of redox reactions involve changes in oxidation number for two or more elements, a few interesting exceptions to this rule do exist as seen in Example 18.1b). Definitions for the complementary processes of this reaction class are correspondingly revised as shown here:


oxidation = increase in oxidation number
reduction = decrease in oxidation number


Number line showing oxidation numbers starting at -5 and increasing by 1 to +5. Oxidation goes to the right signaling a loss of electrons and an increase in oxidation number. This is a reducing agent. Reduction goes to the left signaling a gain of electrons and an decrease in oxidation number. This is an oxidizing agent.
Figure 18.1a Oxidation is a loss of electrons. Reduction is a gain of electrons (credit: graphic by Revathi Mahadevan, CC BY 4.0).

Returning to the reactions used to introduce this topic, they may now both be identified as redox processes. In the reaction between sodium and chlorine to yield sodium chloride, sodium is oxidized (its oxidation number increases from 0 in Na to +1 in NaCl) and chlorine is reduced (its oxidation number decreases from 0 in Cl2 to −1 in NaCl). In the reaction between molecular hydrogen and chlorine, hydrogen is oxidized (its oxidation number increases from 0 in H2 to +1 in HCl) and chlorine is reduced (its oxidation number decreases from 0 in Cl2 to −1 in HCl).

Several subclasses of redox reactions are recognized, including combustion reactions in which the reductant (also called a fuel) and oxidant (often, but not necessarily, molecular oxygen) react vigorously and produce significant amounts of heat, and often light, in the form of a flame. Solid rocket-fuel reactions are combustion processes. A typical propellant reaction in which solid aluminum is oxidized by ammonium perchlorate is represented by this equation:


10Al(s) + 6NH4ClO4(s)→4Al2O3(s) + 2AlCl3(s) + 12H2O(g) + 3N2(g)
The test firing of a small-scale, prototype, hybrid rocket engine planned for use in the new Space Launch System is being developed by NASA. The first engines firing at 3 s (green flame) use a liquid fuel/oxidant mixture, and the second, more powerful engines firing at 4 s (yellow flame) use a solid mixture.

Video source: NASA’s Marshall Space Flight Center. (2014, August 28). NASA tests model of powerful new rocket [Video]. YouTube.

Single-displacement (replacement) reactions are redox reactions in which an ion in solution is displaced (or replaced) via the oxidation of a metallic element. One common example of this type of reaction is the acid oxidation of certain metals:


Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)

Metallic elements may also be oxidized by solutions of other metal salts; for example:

Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) + 2Ag(s)

This reaction may be observed by placing copper wire in a solution containing a dissolved silver salt. Silver ions in solution are reduced to elemental silver at the surface of the copper wire, and the resulting Cu2+ ions dissolve in the solution to yield a characteristic blue color (Figure 18.1b).

This figure contains three photographs. In a, a coiled copper wire is shown beside a test tube filled with a clear, colorless liquid. In b, the wire has been inserted into the test tube with the clear, colorless liquid. In c, the test tube contains a light blue liquid and the coiled wire appears to have a fuzzy silver gray coating.
Figure 18.1b (a) A copper wire is shown next to a solution containing silver(I) ions. (b) Displacement of dissolved silver ions by copper ions results in (c) accumulation of grey-coloured silver metal on the wire and development of a blue colour in the solution, due to dissolved copper ions. (credit: modification of work by Mark Ott in Chemistry (OpenStax), CC BY 4.0).

Example 18.1b

Describing Redox Reactions

Identify which equations represent redox reactions, providing a name for the reaction if appropriate. For those reactions identified as redox, name the oxidant and reductant.

  1. ZnCO3(s) → ZnO(s) + CO2(g)
  2. 2Ga(l) + 3Br2(l) → 2GaBr3(s)
  3. 2H2O2(aq) → 2H2O(l) + O2(g)
  4. BaCl2(aq) + K2SO4(aq) → BaSO4(s) + 2KCl(aq)
  5. C2H4(g) + 3O2(g) → 2CO2(g) + 2H2O(l)


Redox reactions are identified per definition if one or more elements undergo a change in oxidation number.

  1. This is not a redox reaction, since oxidation numbers remain unchanged for all elements.
  2. This is a redox reaction. Gallium is oxidized, its oxidation number increasing from 0 in Ga(l) to +3 in GaBr3(s). The reducing agent is Ga(l). Bromine is reduced, its oxidation number decreasing from 0 in Br2(l) to −1 in GaBr3(s). The oxidizing agent is Br2(l).
  3. This is a redox reaction. It is a particularly interesting process, as it involves the same element, oxygen, undergoing both oxidation and reduction (a so-called disproportionation reaction). Oxygen is oxidized, its oxidation number increasing from −1 in H2O2(aq) to 0 in O2(g). Oxygen is also reduced, its oxidation number decreasing from −1 in H2O2(aq) to −2 in H2O(l). For disproportionation reactions, the same substance functions as an oxidant and a reductant.
  4. This is not a redox reaction, since oxidation numbers remain unchanged for all elements.
  5. This is a redox reaction (combustion). Carbon is oxidized, its oxidation number increasing from −2 in C2H4(g) to +4 in CO2(g). The reducing agent (fuel) is C2H4(g). Oxygen is reduced, its oxidation number decreasing from 0 in O2(g) to −2 in H2O(l). The oxidizing agent is O2(g).

Exercise 18.1b

This equation describes the production of tin(II) chloride:

Sn(s) + 2HCl(g) → SnCl2(s) + H2(g)

Is this a redox reaction? If so, provide a more specific name for the reaction if appropriate, and identify the oxidant and reductant

Check Your Answer[2]

Links to Interactive Learning Tools

Attribution & References

Except where otherwise noted, this page is adapted by David Wegman from “7.2 Classifying Chemical Reactions” In General Chemistry 1 & 2 by Rice University, a derivative of Chemistry (Open Stax) by Paul Flowers, Klaus Theopold, Richard Langley & William R. Robinson and is licensed under CC BY 4.0. ​Access for free at Chemistry (OpenStax)​.

  1. (a) N, +5; (b) Al, +3; (c) N, −3; (d) P, +5
  2. Yes, a single-replacement reaction. Sn(s)is the reductant, HCl(g) is the oxidant.


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Enhanced Introductory College Chemistry Copyright © 2023 by Gregory Anderson; Caryn Fahey; Jackie MacDonald; Adrienne Richards; Samantha Sullivan Sauer; J.R. van Haarlem; and David Wegman is licensed under a Creative Commons Attribution 4.0 International License, except where otherwise noted.

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