Exercise Answers: Module 25

62 Exercise Answers: Module 25 — Technical Mathematics

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$1,728\text{ in}^3$
$46,656\text{ in}^3$
$1,000\text{ mm}^3$
$1,000,000\text{ cm}^3$
the result is very close to $1$ cubic yard: $(112\text{ in}\cdot14\text{ in}\cdot10\text{ in})\cdot3\text{ crates}=47,040\text{ in}^3\approx1.01\text{ yd}^3$
this estimate is also $1$ cubic yard: $(9\text{ ft}\cdot1\text{ ft}\cdot1\text{ ft})\cdot3\text{ crates}=27\text{ ft}^3=1\text{ yd}^3$
around $60$ gallons
yes, the can is able to hold $12$ fluid ounces; the can’s volume is roughly $23.3$ cubic inches $\approx12.9$ fluid ounces.
yes, the can is able to hold $330$ milliliters; the can’s volume is roughly $362$ cubic centimeters, which is equivalent to $362$ milliliters.
$1.53\text{ m}^3$
$3,930\text{ cm}^3$
$30.5\text{ in}^3$
$28.3\text{ m}^3$
$59\text{ yd}^3$
$31\text{ lb}$
$1.1\text{ kg}$
$268\text{ cm}^3$
$33.5\text{ cm}^3$
$8$ to $1$
$1,620\text{ in}^3$
$60\text{ in}^3$
$27$ to $1$