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6.2. Solved Examples: Introduction to Forces; Newton’s Laws

Example 1

A 1550 kg car moving at 10 m/s accelerates to 30 m/s in 10 s. What is the net force applied to the car?

Given:
[latex]v_i = 10\,\text{m}/\text{s}[/latex]
[latex]v_f = 30\,\text{m}/\text{s}[/latex]
[latex]t = 10\,\text{s}[/latex]
[latex]m = 1550\,\text{kg}[/latex]
Find:
[latex]\text{F } =\text{ }?[/latex]

Solution:

  1. Decide which equation works for the question by examining what is given and what needs to be found.
    [latex]F = m \times a[/latex], where [latex]a = \frac{v_f - v_i}{t}[/latex]
  2. Substitute the values for the known quantities in the last equation:
    [latex]a = \frac{v_f - v_i}{t} = \frac{30 - 10}{10} = 2.0\,\text{m}/\text{s}^2[/latex]
    [latex]F = m \times a = 1550 \times 2.0 = 3100\,\text{N}[/latex]

Answer:

[latex]F = 3100\,\text{N}[/latex]

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College Physics – Fundamentals and Applications Copyright © by Daniela Stanescu, Centennial College is licensed under a Creative Commons Attribution-NonCommercial 4.0 International License, except where otherwise noted.