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5.2. Solved Examples: Free Fall

Solved examples

Example 1.   An object is thrown upwards with a velocity of [latex]25 \, \text{m/s}[/latex]

  1. Find the maximum height reached by the object.
  2. Find the time to reach the maximum height.
  3. Find the time the object was in flight.

Given:

[latex]v_i = 25 \, \text{m/s}[/latex]

[latex]v_f = 0 \, \text{m/s}[/latex]

[latex]g = 9.8 \, \text{m/s}^2[/latex]

Find:

[latex]\text{a) } h_{\text{max}} = ?[/latex]

[latex]\text{b) } t_{\text{up}} = ?[/latex]

[latex]\text{c) } t_{\text{total}} = ?[/latex]

Solution:
  1. Decide which equation works to solve the question by examining what information is given and what needs to be found.

    [latex]v_f^2 = v_i^2 - 2gs[/latex]

    Rearrange the equation to express the wanted quantity:

    [latex]h_{\text{max}} = \frac{v_i^2}{2a}[/latex]

    Substitute the values for the known quantities in the last equation:

    [latex]h_{\text{max}} = \frac{v_i^2}{2a} = 31.9 \, \text{m} \approx 32 \, \text{m}[/latex]

    Answer:

    [latex]h_{\text{max}} = 32 \, \text{m}[/latex]


  2. Choose the equation:

    [latex]v_f = v_i - gt[/latex]

    Rearrange the equation:

    [latex]t_{\text{up}} = \frac{v_i}{g}[/latex]

    [latex]t_{\text{up}} = \frac{v_i}{g} = 2.55 \, \text{s} \approx 2.6 \, \text{s}[/latex]

    Answer:

    [latex]t_{\text{up}} \approx 2.6 \, \text{s}[/latex]


  3. Since the object returns to the same level from which it started:

    [latex]t_{\text{up}} = t_{\text{down}}[/latex]

    [latex]t_{\text{total}} = 2 \times t_{\text{up}} = 5.2 \, \text{s}[/latex]

    Answer:

    [latex]t_{\text{total}} = 5.2 \, \text{s}[/latex]

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College Physics – Fundamentals and Applications Copyright © by Daniela Stanescu, Centennial College is licensed under a Creative Commons Attribution-NonCommercial 4.0 International License, except where otherwise noted.