10.3. Practice Sets: Work, Energy, and Power
Chapter Equations
[latex]W = F \times d \times \cos\theta[/latex] (1)
[latex]W = \Delta E[/latex] (The work – energy theorem) (2)
[latex]KE = \frac{1}{2} m v^2[/latex] (3)
[latex]PE = m g h[/latex] (4)
[latex]ME_1 = ME_2[/latex] (Conservation of mechanical energy) (5)
[latex]KE_1 + PE_1 = KE_2 + PE_2[/latex] (6)
[latex]\frac{1}{2} m v_1^2 + m g h_1 = \frac{1}{2} m v_2^2 + m g h_2[/latex] (7)
[latex]P = \frac{W}{t} = \frac{\Delta E}{t} = F \times v[/latex] (8)
Try It!
- You push very hard a piano, but you are not able to move it. Are you doing work on the piano?
- The speed of a car triples during a trip. By what factor does the kinetic energy increases?
- A car travelling at velocity [latex]v[/latex] can stop in a minimum distance of [latex]d[/latex]. Use an energy approach to find the minimum stopping distance for the same car travelling now at a speed of [latex]2v[/latex].
- A ball is thrown straight up. Ignoring the air resistance, at what point would the ball have the most amount of energy?
Practice
- What force is needed to bring an [latex]850 \, \text{kg}[/latex]car to rest from a speed of [latex]100 \, \text{km/h}[/latex] in a distance of [latex]20 \, \text{m}[/latex]? Calculate from energy consideration.
Answer:[latex]16{,}399 \, \text{N}[/latex] - The car going on the roller coaster in the figure has a mass of [latex]370 \, \text{kg}[/latex]. Neglect friction and air resistance.
10.6. image goes here
Find:
- The potential and the kinetic energy of the car in point A.
Answer:[latex]PE = 36{,}260 \, \text{J}, \quad KE = 740 \, \text{J}[/latex] - The total mechanical energy of the car in point B.
Answer:[latex]ME = 37{,}000 \, \text{J}[/latex] - The speed of the car in point C.
Answer:[latex]v_c = 11.9 \, \text{m/s}[/latex] - The maximum height the car can reach (point D)
Answer:[latex]10.2 \, \text{m}[/latex]
- The potential and the kinetic energy of the car in point A.
- A child on a swing being held at a certain height above its lowest position has a total mechanical energy of [latex]4800 \, \text{J}[/latex]. When the swing is released, it reaches the lowest position with a speed of [latex]8.5 \, \text{m/s}[/latex]. Assume no air friction.
- Find the total mechanical energy of the system at its lowest position.
Answer:[latex]4800 \, \text{J}[/latex] - Find the mass of the child–swing system.
Answer:[latex]132.9 \, \text{kg}[/latex]
- Find the total mechanical energy of the system at its lowest position.
- A worker is pulling a [latex]12 \, \text{kg}[/latex] crate on the floor, with a rope that makes a [latex]25 \, \text{degrees}[/latex] angle with the horizontal applying a force of [latex]65 \, \text{N}[/latex]. If the worker is moving the crate a distance of [latex]15 \, \text{m}[/latex] in [latex]12 \, \text{s}[/latex], find:
- The work done by the worker.
Answer:[latex]884 \, \text{J}[/latex] - The power developed by the worker.
Answer:[latex]74 \, \text{W}[/latex]
- The work done by the worker.
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- A [latex]15 \, \text{kg}[/latex] package slides on a level floor at [latex]1.2 \, \text{m/s}[/latex]. Find the work needed to bring the package to a stop. Use an energy approach.
Answer:[latex]-10.8 \, \text{J}[/latex] - If the force applied to the package is [latex]14 \, \text{N}[/latex], what is the distance travelled by the package before it stops?
Answer:[latex]0.77 \, \text{m}[/latex]
- A [latex]15 \, \text{kg}[/latex] package slides on a level floor at [latex]1.2 \, \text{m/s}[/latex]. Find the work needed to bring the package to a stop. Use an energy approach.
- How long will it take a [latex]1250 \, \text{kg}[/latex] car with a useful power output of [latex]50 \, \text{hp}[/latex] to reach a speed of [latex]20 \, \text{m/s}[/latex] starting from rest?
Answer:[latex]6.7 \, \text{s}[/latex]
Challenge Questions
Drag and drop the correct answer in the designated area.
Text Version of the Challenge Question(s)
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A [latex]20 \, \text{kg}[/latex] package moving at [latex]1.0 \, \text{m/s}[/latex] is given a push. Knowing that the work done on the package is [latex]120 \, \text{J}[/latex], find the speed of the package at the end of the push. Use an energy approach.
Answer: [latex]3.6 \, \text{m/s}[/latex]