11.6 North-West Corner Rule (NWCR)
The North-West Corner Method (NWCM) is a straightforward technique used to generate an initial feasible solution for a balanced transportation model. While it does not consider transportation costs during allocation, it provides a valid starting point for further optimization.
This method is named after the north-west (upper-left) cell of the transportation tableau, where the allocation process begins.
NWCR Steps
- Start at the North-West Cell (Top-Left Corner):
Allocate as much as possible to the cell in the first row and first column (cell (1,1)), subject to the available supply and demand. - Adjust Supply and Demand:
Subtract the allocated quantity from both the supply of the row and the demand of the column. - Eliminate Satisfied Rows or Columns:
If the supply for a row or the demand for a column is fully satisfied (i.e., reduced to zero), that row or column is considered complete and is crossed out (highlighted in grey in visual representations). - Move to the Next Available Cell:
Proceed to the next cell to the right (if a row is still active) or downward (if a column is completed) and repeat the allocation process. - Continue Until Completion:
Repeat the above steps until all supply and demand values are fully allocated.
Once the initial allocation is complete, the total transportation cost can be calculated by multiplying the quantity allocated to each cell by its corresponding unit transportation cost and summing the results across the tableau.
Example: Mega Farms Inc.
Mega Farms Inc. operates three strawberry farms (S1, S2, and S3) which supplies four regional markets (D1, D2, D3, and D4). The supply capacities and market demands are as follows:
- Supply Capacities:
- S1: 60 cases
- S2: 80 cases
- S3: 100 cases
- Market Demands:
- D1: 50 cases
- D2: 70 cases
- D3: 80 cases
- D4: 40 cases
The transportation cost per case (in $) from each farm to each market is provided in the following tableau:
| D1 | D2 | D3 | D4 | Supply | |
|---|---|---|---|---|---|
| S1 | $6 | $2 | $14 | $8 | 60 Cases |
| S2 | $4 | $12 | $10 | $18 | 80 Cases |
| S3 | $16 | $6 | $6 | $4 | 100 Cases |
| Demand | 50 Cases | 70 Cases | 80 Cases | 40 Cases |
Mega Farms Inc. wants to determine how many cases should be sent from which farm to which market so that the total cost of transportation is minimized.
Determining the Total Transportation Cost Using the North-West Corner Method
The tableau for this model is shown below:
| D1 | D2 | D3 | D4 | Supply | |
|---|---|---|---|---|---|
| S1 | $6 | $2 | $14 | $8 | 60 |
| S2 | $4 | $12 | $10 | $18 | 80 |
| S3 | $16 | $6 | $6 | $4 | 100 |
| Demand | 50 | 70 | 80 | 40 |
The steps in solving this problem are:
Step 1: Allocate to (S1, D1)
- Allocate 50 units (the demand of D1).
- Update:
- S1 remaining supply = [latex]60 - 50 = 10[/latex]
- D1 demand fulfilled = [latex]50 - 50 = 0[/latex]
| D1 | D2 | D3 | D4 | Supply | |
|---|---|---|---|---|---|
| S1 | (50) $6 | $2 | $14 | $8 | |
| S2 | $4 | $12 | $10 | $18 | 80 |
| S3 | $16 | $6 | $6 | $4 | 100 |
| Demand | 70 | 80 | 40 |
Step 2: Allocate to (S1, D2)
- Allocate 10 units (the remaining amount in S1)
- Update:
- S1 exhausted
- D2 remaining demand = [latex]70 - 10 = 60[/latex]
| D1 | D2 | D3 | D4 | Supply | |
|---|---|---|---|---|---|
| S1 | (50) $6 | (10) $2 | $14 | $8 | |
| S2 | $4 | $12 | $10 | $18 | 80 |
| S3 | $16 | $6 | $6 | $4 | 100 |
| Demand | 0 | 80 | 40 |
Step 3: Allocate to (S2, D2)
- Allocate 60 units (the remaining demand in D2)
- Update:
- S2 remaining supply = [latex]80 - 60 = 20[/latex]
- D2 demand fulfilled
| D1 | D2 | D3 | D4 | Supply | |
|---|---|---|---|---|---|
| S1 | (50) $6 | (10) $2 | $14 | $8 | 0 |
| S2 | $4 | (60) $12 | $10 | $18 | |
| S3 | $16 | $6 | $6 | $4 | 100 |
| Demand | 0 | 80 | 40 |
Step 4: Allocate to (S2, D3)
- Allocate 20 units (the remaining supply from S2)
- Update:
- S2 exhausted
- D3 remaining demand = [latex]80 - 20 = 60[/latex]
| D1 | D2 | D3 | D4 | Supply | |
|---|---|---|---|---|---|
| S1 | (50) $6 | (10) $2 | $14 | $8 | 0 |
| S2 | $4 | (60) $12 | (20) $10 | $18 | |
| S3 | $16 | $6 | $6 | $4 | 100 |
| Demand | 0 | 0 | 40 |
Step 5: Allocate to (S3, D3)
- Allocate 60 units (the remaining demand in D3)
- Update:
- S3 remaining supply = [latex]100 - 60 = 40[/latex]
- D3 demand fulfilled
| D1 | D2 | D3 | D4 | Supply | |
|---|---|---|---|---|---|
| S1 | (50) $6 | (10) $2 | $14 | $8 | 0 |
| S2 | $4 | (60) $12 | (20) $10 | $18 | 0 |
| S3 | $16 | $6 | (60) $6 | $4 | |
| Demand | 0 | 0 | 40 |
Step 6: Allocate to (S3, D4)
- Allocate the remaining 40 units
- Update:
- S3 exhausted
- D4 demand fulfilled
| D1 | D2 | D3 | D4 | Supply | |
|---|---|---|---|---|---|
| S1 | (50) $6 | (10) $2 | $14 | $8 | 0 |
| S2 | $4 | (60) $12 | (20) $10 | $18 | 0 |
| S3 | $16 | $6 | (60) $6 | (40) $4 | |
| Demand | 0 | 0 | 0 |
After completing the allocation process using the North-West Corner Method, all market demands have been fully satisfied, and the available supply from all farms has been completely utilized. This indicates that a feasible solution has been reached.
To determine the total transportation cost of this initial solution, we multiply the quantity allocated to each cell by its corresponding unit transportation cost and sum the results:
[latex]\begin{align*} \text{Total Cost}&= (\small\text{S1/D1} \times \small{6}) + (\small\text{S1/D2} \times 2) + (\small\text{S2/D2} \times 12)+ (\small\text{S2/D3} \times 10) + (\small\text{S3/D3} \times 6) + (\small\text{S3/D4} \times 4) \\ \text{Total Cost}&= (50 \times 6) + (10 \times 2) + (60 \times 12) + (20 \times 10) + (60 \times 6) + (40 \times 4)\\ \text{Total Cost}&= 300 + 20 + 720 + 200 + 360 + 160 \\ \text{Total Cost}&= 1760 \end{align*}[/latex]
Thus, the initial basic feasible solution obtained using the North-West Corner Method results in a total transportation cost of $1760.
It is important to note that while this method provides a valid starting point, it does not guarantee the optimal solution. Therefore, in the following sections, we will evaluate the total transportation cost using two more refined methods:
- Least Cost Method (LCM)
- Vogel’s Approximation Method (VAM)
These methods incorporate cost considerations during the allocation process and are likely to yield more cost-efficient solutions
Video: Transportation Problem - NWC Initial Allocation
Video: "Transportation Models : North West Corner Initial Allocation" by Maths Resource [8:45] is licensed under the Standard YouTube License.Transcript and closed captions available on YouTube.