2.4 – IUPAC Nomenclature

Introduction

Chapter 2.1.1. introduced line-angle drawings  to draw organic compounds. The ability to draw and recognize these structures is an important skill, as is the ability to name these structures. The International Union of Applied and Pure Chemistry (IUPAC) has standardized the naming of organic compounds by creating a list of rules and regulations to abide by.

This chapter will introduce how to name organic compounds using IUPAC rules.

 

Prefixes, Parent Chains and Suffixes

 When naming an organic structure, or drawing an organic structure based on its name, look for these three key details:

  1. The suffix indicates the functional group.
  2. The parent chain indicates the number of carbon atoms in the longest chain that contains the highest priority functional group.
  3. The prefix indicates the identity and location of substituents on the parent chain. A substituent is an atom or a group of atoms that is attached to the parent chain.

Once these details have been identified, the name of the compound is constructed as follows:

Prefix + parent + suffix

 

Identifying the functional groups and priority

When naming organic molecules, identify the functional groups first, as this will aid in determining the parent chain. For compounds with more than one functional group, the highest priority functional group defines the final suffix of the parent chain. Lower priority functional groups are considered substituents and are named as prefixes. Figure 2.4.a. shows functional groups listed in priority sequence. Table 2.4.a. shows the name of the functional group when used as a prefix or as a suffix.

 

Diagram showing “Carboxylic acid, ester > aldehyde, ketone > alcohol > alkene, alkyne”
Figure 2.4.a. Functional groups in order of priority. Functional groups on the left take priority over those to the right.

 

Table 2.4.a. Functional groups and their IUPAC prefixes and suffixes.

Functional Group Structure Prefix Suffix
fluorine fluoro– None
chlorine chloro– None
bromine bromo– None
iodine iodo– None
ether alkoxy– –ether
benzene phenyl– –benzene
alkane alkyl– –ane
alkene alk–#–en–yl– –ene
alkyne alk–#–yn–yl– –yne
alcohol hydroxy– –ol
aldehyde None –al
ketone None –one
carboxylic acid None –oic acid
ester None –oate
Primary amine None –amine
Secondary amine None –amine
Tertiary amine None –amine
Primary amide None –amide
Secondary amide None –amide
Tertiary amide None –amide

An example of determining priority is shown below in Figure 2.4.b. There are two functional groups present: alcohol and aldehyde. Figure 2.4.a. shows that aldehydes have a higher priority than alcohols, so the aldehyde will be the final suffix (name will end with “–al”), while the alcohol will be a substituent and use the prefix “hydroxy–”.

A linear zig-zag line-bond structure. There are 4 corners designating carbon. From right to left, the second corner has a bond to OH. The last corner is doubly bound to an O.
Figure 2.4.b. Structure of 3–hydroxybutanal. The aldehyde functional group has a higher priority than the alcohol functional group, so the aldehyde will determine the final suffix (–al) while the alcohol will be treated as a substituent (hydroxy).

(The full solution to this problem can be found in Chapter 5.1).

 

The Parent Chain

Once the functional groups have been identified and priority has been assigned, the next step is to identify the parent chain. The parent chain is the carbon chain that contains the highest priority functional group and the greatest number of carbon atoms.

For example, the molecule shown in Figure 2.4.c. is an alkane. To name this molecule, we must identify the chain containing the greatest number of carbon atoms. The parent chain is the path shown in red path, as it contains the most carbon atoms: seven. In comparison, the blue path contains six carbon atoms, and should not be chosen as the parent chain.

A branching alkyl chain in line-bond format, in a zig-zag. The longest consecutive chain is labelled in red from 1-7 on corners, where it has a branch at carbons 2 and 3 being a methyl group. There is a chain in blue labelling 1-6, with a branch at carbon 2 being an isopropyl group.
Figure 2.4.c. Identifying the parent chain of the molecule 2,3-dimethylheptane. The red path indicates the parent chain, as this path contains the most carbons (seven). The blue path contains fewer carbons (six) and should not be chosen as the parent chain.

The name of the parent chain depends on the number of carbon atoms. Table 2.4.b below summarizes parent chains containing up to 10 carbons.

Table 2.4.b. Naming parent chains and alkyl substituents containing 1-10 carbons.

Parent Alkane Name Alkyl Substituents Number of Carbon Atoms
methane methyl 1
ethane ethyl 2
propane propyl 3
butane butyl 4
pentane pentyl 5
hexane hexyl 6
heptane heptyl 7
octane octyl 8
nonane nonyl 9
decane decyl 10

Note that there are common propyl and butyl branched substituents named “isopropyl” and “tert–butyl” respectively, which are pictured below. You will see these substituents often in this course and in second year, so it’s important to become familiar with their structure.

Two molecular structures, the left being isopropyl, with R bound to a branched carbon bound to two methyl groups. The right is tert-butyl, with R bound to a branched carbon bound to three methyl groups.
Figure 2.4.d. Structures of the common propyl and butyl substituents, “isopropyl” and “tert–butyl”. Note that “R” denotes an alkyl substituent.

The molecule shown below in Figure 2.4.e is named 2,3-dimethylheptane. In the name, heptane comes from the fact that there are seven carbon atoms in the parent chain (hept) and it is an alkane (suffix –ane). We will examine the prefix (2,3-dimethyl–) in the next section.

Branch Points

The parent chain may not include all carbon atoms in the molecule. For example, in Figure 2.4.e, the parent chain (shown in red) contains two branch points, at positions 2 and 3 in the chain. A branch point refers to a point where a substituent diverges from the parent chain.

If a compound contains two chains of equal length, the parent chain is designated to be the chain with more branch points. For example, for the molecule shown in Figure 2.4.e, the red path and the blue path both have seven carbon atoms, but the red path has three branch points while the blue path has two branch points (shown in green). The red path should therefore be chosen as the parent chain.

Two depictions of the same linear and zig-zag molecule. The one on the left is labelled with numbers 1-7 from right to left, each number being on the edge of the zig-zag. There are edges labelled 2, 3 and 4 coloured green with a methyl, ethyl and methyl group branching out of each respectively. The one on the right is labelled with numbers 1-7 from right to left. There are edges labelled 3 and 4 coloured green with an isopropyl and methyl branching out of each respectively.
Figure 2.4.e. Identifying the parent chain of a molecule based on the number of branch points, shown in green circles. Two possibilities are shown in red on the left and blue on the right, both of which have seven carbon atoms. The red path on the left should be chosen as the parent chain, because it contains more branch points (3) whereas the blue path contains fewer branch points (2).

When deciding which end of the parent chain to begin numbering, first choose the path that gives the highest priority functional group the lowest number. If both paths give the same numbering to the highest priority functional group, or the priority of all side chains/functional groups are the same, then choose the path that reaches a branch point sooner. For example, for the molecule shown in Figure 2.4.f, the red path and the blue path both have eight carbon atoms and one branching point. To number the parent chain correctly, the blue path should be chosen because the branch point occurs sooner, at position 4. In comparison, the red path has the first branch point at position 5.

A linear molecule in a zig-zag orientation, with a single branching ethyl group circled. The molecule is labelled 1-8 on each edge, from left to right in red and right to left in blue. “4-ethyl” is written in blue, and “5-ethyl” is written in red.
Figure 2.4.f. There are two possibilities to number the parent chain in this molecule, shown in red below the atoms and blue above the atoms, both of which have eight carbon atoms. The blue path should be chosen as the parent chain, because it reaches the branch point sooner (position 4), compared to the red path that reaches the branch point at a later position (position 5).

 

Naming the Branches

To name alkyl branches attached to the parent chain, use the prefix associated with the carbon length (Table 2.4.b), followed by –yl. The position of the branch should be indicated before the branch name with a hyphen separating the number and branch name.

For example, the molecule shown earlier in Figure 2.4.f has one substituent with two carbons. The substituent is named “ethyl”, and we specify that it occurs at position 4 in the parent chain by writing “4-ethyl”. Therefore, the compound shown in Figure 2.4.f is named 4-ethyloctane.

If there is more than one substituent on the parent chain, then the substituents are listed in alphabetical order. For example, the molecule in Figure 2.4.g has two substituents: a fluoro group at position 2 and an ethyl group at position 4 of the parent chain. The word ethyl comes earlier in the alphabet than the word fluoro, and therefore the ethyl group is listed first in the prefixes. There molecule is an alkane with seven carbon atoms in the parent chain, so it is called heptane. Thus, this compound is named 4-ethyl-2-fluoroheptane.

A diagram of two of the same molecule labelled differently. The top is a linear zig-zag molecule labelled 1-7 from left to right on each edge. There is a bond to F on carbon 2 and to ethyl on carbon 4. The bottom is the same molecule, only it is only labelled “2-fluoro” on carbon 2 and “4-ethyl” on carbon 4, with each of these functional groups circled.
Figure 2.4.g. Naming molecules with more than one substituent. The parent chain is an alkane with seven carbons. There are two substituents in this molecule: a fluoro group at position 2 and an ethyl group at position 4. This molecule is named “4-ethyl-2-fluoroheptane”.

If a molecule has more than one identical substituent, then the prefixes di-, tri-, tetra-, etc., are used to indicate how many identical substituents there are, with the locations on the parent chain separated by commas. For example, let’s once again consider the molecule shown in Figure 2.4.c.

  • The molecule is an alkane (-ane).
  • There are seven carbon atoms in the parent chain (hept).
  • There are two branching points at position 2 and 3, both containing methyl substituents (2,3-dimethyl-).

Therefore, this molecule is named 2,3-dimethylheptane.

A prefix that indicates the quantity of identical substituents (di-, tri-, tetra-, etc.) is not included in alphabetizing the substituents. For example, consider the molecule shown in Figure 2.4.e.

  • The molecule is an alkane (-ane).
  • There are seven carbon atoms in the parent chain (hept).
  • There are three branching points: positions 2 and 4 contain methyl groups (2,4-dimethyl-) while position 3 contains an ethyl group (3-ethyl-).
  • Note that ethyl comes first alphabetically compared to methyl; the prefix di- in front of methyl does not count (3-ethyl-2,4-dimethyl-).

Therefore, this molecule is named 3-ethyl-2,4-dimethylheptane.

Combining the Parent Chain and Substituents

When combining the branches and the parent chain to fully name the molecule, write the name as one word, with hyphens separating prefixes, and commas separating numbers. List all substituents in alphabetical order (without alphabetizing prefixes like di, tri, tetra, etc.).

Figure 2.4.h. below illustrates these conventions using the molecule 5,5-diethyl-3-methyloctane.

  • The molecule is an alkane (-ane)
  • There are eight carbon atoms in the parent chain (oct)
  • There are three branching points: position 3 contains a methyl group (3-methyl-) while position 5 contains two ethyl groups (5,5-diethyl-).
  • Note that ethyl comes first alphabetically compared to methyl; the prefix di- in front of ethyl does not count when alphabetizing (5,5-diethyl-3-methyl-).

Therefore, this molecule is named 5,5-diethyl-3-methyloctane.

A scheme of the three steps of naming 5,5-diethyl-3-methyloctane, which is drawn as a zig-zag line-bond molecule. The first step has the parent chain labelled with numbers 1-8 from left to right. Beside the molecule, “functional group=alkane - -ane”, “8 carbons – oct-” and “parent chain = octane” is written. The second step has the same molecule, only the branch points at carbons 3 and 5 have their alkyl chains circled. On carbon 3, a methyl group is circled, and carbon 5 has two ethyl groups circled. Beside the molecule, “1 branch has one carbon – methyl, 2 branches have 2 carbons – diethyl", “branch positions – carbons 3 and 5” and “substituent name = 5,5-diethyl" are written. The third step shows the same previously labelled molecule, with 5,5-diethyl-3-methyloctane written next to it.
Figure 2.4.h. Steps to name the molecule 5,5-diethyl-3-methyloctane. First, begin with identifying the parent chain. Next, identify and name the substituents. Last, put the parent chain and substituents together to yield the final name.

When determining the direction to begin numbering the parent chain, if both paths contain branches at the same number, alphabetization is used to determine the lowest number.

An example is seen below in Figure 2.4.i. Both the red and blue path contain branch points at the same positions (4 and 6). In the blue path, carbon 4 contains a propyl group while carbon 6 contains an ethyl group. In the red path, carbon 4 contains an ethyl group while carbon 6 contains a propyl group. Since the red path contains an ethyl group on the first branch, the red path should be chosen takes priority, as the letter “E” comes first alphabetically.

An image of 4-ethyl-6-propylnonane in zig-zag format, labelled with the numbers 1-9 on its parent chain from both left to right, in blue, and right to left, in red. Left to right contains the propyl group at position 4, and right to left has the ethyl group at position 4. On the right, “4-propyl 6-ethyl” is written in blue, and “4-ethyl 6-propyl” is written in red.
Figure 2.4.i. If the number of carbon atoms in the parent chain and branches present are the same, then alphabetization is used to determine the lowest number.

Table 2.4.a mentioned the suffixes and prefixes used for naming the various functional groups. Esters are a special case of combining the parent chain and substituents using the suffixes and prefixes, as shown in the following example (Figure 2.4.j).

(The full solution to this problem can be found in Chapter 5.1).

 

A molecule in line-bond zig-zag format, with 4 connecting edges meeting an O on the right at the fourth carbon. This O is bound to another carbon to the right. The fourth carbon from the left is doubly bound to an oxygen, and the second carbon to the left is bound to a F branch.
Figure 2.4.j. Structure of the unknown ester that will be named below.

To name esters, split the molecule into two portions (Figure 2.4.k): the portion containing the carbonyl (C=O) group, shown in green, and the substituent that is singly bonded to oxygen, shown in blue. The blue portion is named first, like a prefix, and the green portion is named last.

The previous molecule in 2.4.j, depicted as a zig-zag, with an ester group where an O replaces one corner. The left of this oxygen is circled green, and the right is circled blue.
Figure 2.4.k. To name esters, split the molecule into the two groups: the portion containing the carbonyl group (C=O, shown in a green box) and the group singly bonded to oxygen (shown in a blue box).

The first step is to name the group singly bonded to oxygen (in blue). In this example, there is one carbon atom (methyl). The next step is to name the portion containing the carbonyl group (in green). Begin numbering this portion starting at the carbonyl carbon atom (this is carbon 1). At carbon 3, there is a fluorine atom (3-fluoro- prefix). The parent chain is 4 carbons long, derived from butane, while the suffix for esters is “-oate” (butanoate). Note that the two portions that comprise the ester (methyl and 3-fluorobutanoate) are separated by a space rather than a hyphen. Therefore, the final name is methyl 3-fluorobutanoate (Figure 2.4.l).

 

The previous molecule in 2.4.j, depicted as a zig-zag, with an ester group where an O replaces one corner. The left of this oxygen is labelled 1-4 from right to left on the carbon edges, and on carbon labelled 3 there is an F branch. The right of the O is a single carbon, labelled 1. The left is circled and labelled “methyl”, and the right is circled and labelled “3-fluorobutanoate”. Below is written 3-fluorobutanoate.
Figure 2.4.l. Structure of the ester methyl 3-fluorobutanoate. When naming esters, the group singly bonded to oxygen is named first (methyl), while the portion containing the carbonyl group is named last (3-fluorobutanoate).

 

Naming Rings

To name the parent chain for cyclic compounds, indicate the number of carbon atoms in the ring, and add the prefix “cyclo”. If there is more than one substituent attached to the ring, number the ring in such a way that the lowest numbered substituent has the highest priority, and continue numbering the ring so that the substituents have the lowest possible number. An example is seen in Figure 2.4.m. There are two functional groups on the cyclopentane ring: an alcohol and an alkyl group. Alcohols have a higher priority, so the ring is labeled starting with carbon 1 at the alcohol, while the methyl group is at carbon 2.

A scheme of the steps involved in naming 2-methylcyclopentanol. The molecule is depicted as a pentagon with a line coming from two edges next to each other, one of which is attached an OH. The top step shows the molecule labelled 1-5 clockwise around the pentagon, starting at the edge attached to the OH. Below this is the molecule with the single line branch circled. Below this is the same molecule, with the same numbering and labelled as previously shown, only the circled line is labelled “2-methyl”.
Figure 2.4.m. Steps to name the cyclic compound 2-methylcyclopentanol. First, identify the functional groups to determine priority and name the parent chain. Next, name the branches. Finally, put the branches and parent chain together and add the prefix “cyclo-” before the name of the parent chain.

If the substituents have equal priority, then alphabetization is used to determine the numbering scheme. Note that if a substituent is not numbered, it is implied to be at position 1. Figure 2.4.n shows both conventions. The only functional group present is an alkane, so alphabetization is used to determine numbering. The letter “E” comes before the letter “M” in the alphabet, so the numbering will begin with the ethyl group at position 1. The compound can be named 1-ethyl-3-methylcycloheptane or ethyl-3-methylcycloheptane, as the lack of a number before a substituent suggests that it is at position 1.

A scheme of the steps involved in naming 3-methylcycloheptane. The molecule is depicted as a heptagon, with a methyl substituent on of its edges, and an ethyl substituent two edges over. There are blue numbers from 1-7 in blue going clockwise around the heptagon, starting at the methyl group, and red numbers from 1-7 going counterclockwise around the heptagon, starting at the ethyl group.
Figure 2.4.n. Steps to name the cyclic compound 1-ethyl-3-methylcycloheptane. The first step is to identify the parent chain and functional groups, adding the prefix “cyclo­-” to denote the ring. Next, identify and name any substituents. In this case, the parent chain and functional groups yields cycloheptane, while the substituents are 1-ethyl and 3-methyl, giving 1-ethyl-3-methylcycloheptane.

Converting from Name to Structure

Throughout this chapter, we’ve discussed how to name organic molecules based on their structure. It is also important to be able to recognize and draw the organic molecules from their IUPAC name.

One example is to draw the structure that represents the name 5-fluoro-6,7-dimethyloctan-2-one. The first step is to look at the final suffix and identify the functional group, as that indicates the parent chain. In this example, the final suffix is “–one”. This corresponds to a ketone being the highest priority functional group in the parent chain.

Next, look for the number of carbons in the parent chain, which is located directly before the final suffix. In this example, “octan”, indicates that 8 carbons make up the parent chain. The number 2 in front of “one” denotes the position of that functional group (a ketone) in the parent chain. Therefore, the 8-carbon parent chain has a ketone at position 2 (Figure 2.4.o).

A molecule in zig-zag in line-bond format, labelled 1-8 on its edges from right to left. The second edge is doubly bound to oxygen.
Figure 2.4.o. The first step when converting from the name to the structure of the organic molecule is to identify the parent chain and highest priority functional group. This name ends in “octan-2-one”, so the parent chain is 8 carbon atoms long with a ketone at position 2.

Next, identify the remaining substituents. One substituent listed is “5-fluoro”, meaning there is a fluorine substituent at position 5 of the parent chain. Other substituents listed are “6,7-dimethyl”, so there are 2 methyl groups on positions 6 and 7 of the parent chain (Figure 2.4.p).

A molecule in zig-zag in line-bond format, labelled 1-8 on its edges from right to left. The second edge is doubly bound to oxygen, the fifth is branched to be bound to an F, and the sixth and seventh are both branched to be bound to a single carbon.
Figure 2.4.p. The next step when converting from the name to the structure of the organic molecule is to identify the substituents, including 5-fluoro and 6,7-dimethyl”.

(The full solution to this problem can be found in Chapter 5.1).

 

Challenging Example

Using the rules from this past chapter, we will work through the example below (Figure 2.4.q).

A molecule drawn as a zig-zag in line-bond format. From left to right, there are 8 edges, or carbons, in the most linear portion of the molecule, until it reaches an oxygen of an ester group. The second and third edges have two lines connecting them. The second edge has a single carbon branch, the third edge has single carbon branch which itself branches to two more carbons, the fourth edge has an OH branched to it and the fifth edge has a hexagonal benzene ring branching to it. The carboxyl portion of the ester group has 5 edges.
Figure 2.4.q. Unknown molecule to be named.

The first step is to identify the functional groups and parent chain (Figure 2.4.r). This molecule contains an ester, alcohol, phenyl group, and alkene. The ester is the highest priority functional group, so it will determine the final suffix. The portion containing the carbonyl (C=O) group (numbered in blue) contains 5 carbons, so the name of the molecule will end in “pentanoate”. The substituent that is singly bonded to oxygen contains 9 carbons in its longest chain (numbered in red), so the prefix will be “non–”. Every other substituent present will be treated as a branch, and the position of the alkene will be specified.

The previously depicted molecule in 2.4.q, labelled on its edges 1-9 from right to left, to the left of the oxygen of the ester, and labelled 1-5 from left to right, to the right of the ester group.
Figure 2.4.r. The first step in naming organic molecules is to identify the functional groups and parent chain. The ester is the highest priority functional group, so it will determine the final suffix. The portion containing the carbonyl group is numbered in blue, while the portion singly bonded to oxygen is numbered in red.

After identifying the parent chain, look for the branches. In this molecule, there are no branches in the carbonyl-containing portion, and five branches in the substituent singly bonded to oxygen: 3-phenyl, 4-methyl, 5-hydroxy, 6-isopropyl and 7-ethyl. In alphabetical order, these prefixes are: 7-ethyl-5-hydroxy-6-isopropyl-4-methyl-3-phenyl.

The previously depicted molecule with, from left to right, 7-ethyl, 6-isopropyl, 5-hydroxy, 4-methyl and 3-phenyl circled and labelled as branches from the main chain.
Figure 2.4.s. After identifying the parent chain, identify and name the branches present. In this molecule, there are 5 branches: 3–phenyl, 4–methyl, 5–hydroxy, 6–isopropyl and 7–ethyl.

Also note the alkene present between carbon 6 and 7. Functional groups that involve two carbon atoms (such as alkenes and alkynes) are identified by the lower numbered carbon atom, in this case carbon 6. The chain that is singly bonded to the oxygen group contains 9 carbons (nonane), with an alkene at position 6 (6-ene), and is bonded to the carbonyl group at position 1 of the chain (1-yl). Therefore, it is named “non-6-en-1-yl” (without considering the branches in this chain).

For the substituent singly bonded to oxygen, combining all aspects leads to the name: 7-ethyl-5-hydroxy-6-isopropyl-4-methyl-3-phenylnon-6-en-1-yl.

The final step is putting the name together. Remember that branches are placed as prefixes before the parent chain, and the portion that is singly bonded to oxygen is named before the carbonyl-containing portion, with a space between each portion. Therefore, the final name of the molecule would be: 7-ethyl-5-hydroxy-6-isopropyl-4-methyl-3-phenylnon-6-en-1-yl pentanoate.

A drawing of 7-ethyl-5-hydroxy-6-isopropyl-4-methyl-3-phenylnon-6-en-1-yl pentanoate.
Figure 2.4.t. Structure of 7-ethyl-5-hydroxy-6-isopropyl-4-methyl-3-phenylnon-6-en-1-yl pentanoate.

 

 

(Click here for full solution).

 

Key Takeaways

Below is a checklist to ensure you have correctly named the organic molecule:

  1. Have you identified all functional groups in the molecule?
  2. Have you assigned priority to the functional groups using Figure 2.4.a. as a guide?
  3. Have you identified the parent chain?
    Remember: to identify the parent chain, choose the path that contains more branch points and follows alphabetization if applicable.
  4. Have you identified and named the branches?
  5. Have you placed the branches in alphabetical order (not including di-, tri­-, etc.)?
  6. Is the molecule a ring?
    If so, include the prefix “cyclo–”
  7. Have you put the names of the branches and parent chain together to yield the final name, with the branches first and the parent chain last?

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Organic Chemistry and Chemical Biology for the Students by the Students! (and the Profs...) Copyright © 2023 by Emma Abreu; Anumta Amir; Anthony Chibba; Jim Ghoshdastidar; Sharonna Greenberg; Angela Liang; Layla Vulgan; and Shuoyang Wang is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.

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